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Jq concat string with variable

I am trying to read my distconfig.json file and set the properties with the above variables. tmp=$ (mktemp) jq '.Origins.Items [0].DomainName = "$DOMAIN_NAME_BUILT"' distconfig.json > "$tmp" && mv "$tmp" distconfig.json The command is working, but it is passing in the variable as a string to my new json file.

2020. 4. 24. · This pattern variable says “find K2 followed by an equals sign, then some arbitrary text, then a comma”. . It also stores the arbitrary text in the variable k2_value.The value is. The concat() method joins two or more strings. The concat() method does not change the existing strings. The concat() method returns a new string. Syntax. string.concat(string1, string2, ..., stringX) Parameters. Parameter: Description: string1, string2,... stringX: Required. The strings to be joined. Return Value. 2016. 7. 31. · Concatenate variable with a string to obtain another variable. I have a function which has 1 parameter: SUB CalendarFromField (_param1, _param2) What I am trying to do is concatenate _param with a string to obtain another string variable which I will use as a table name later: let new_table_name = ['New_table_' & '$ (_param1)']; let resident.

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1 day ago · Concatenate arrays: jq 'add' Flatten an array: jq 'flatten' Create a range of numbers: jq '[range(2;4)]' Display the type of each item: jq 'map(type)' Sort an array of basic type: jq 'sort'. 2020. 4. 18. · And there you have it, when trying to combine state with a string you need to indicate which part of the text is a variable and which is a string literal. If you are looking to get.

2015. 11. 24. · Essentially eval is extracting the value from that concatenated string variable name by simply evaluating the variable name which returns the associated value, then assigning it to row[0]. Instead, I'd recommend instantiating a dictionary where the keys are your string keywords i.e.: "ARSSPAN" and the values are the associated int value.


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